0=144-48n+4n^2

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Solution for 0=144-48n+4n^2 equation: 



0=144-48n+4n^2

We move all terms to the left:

0-(144-48n+4n^2)=0

We add all the numbers together, and all the variables

-(144-48n+4n^2)=0

We get rid of parentheses

-4n^2+48n-144=0

a = -4; b = 48; c = -144;
Δ = b2-4ac
Δ = 482-4·(-4)·(-144)
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$n=\frac{-b}{2a}=\frac{-48}{-8}=+6$

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